Any of y'all know what's going on with this resistor? Brown black gold gold black is a bit unusual. From what I've found I'm pretty sure it's a 1 ohm resistor (±5%), but I'm unsure about that last black band. From what I've found, it's either the temp. coefficient, the reliability, or it's telling me it's a wirewound resistor. Given this is a generic 5V power supply, I *think* it's the last one, but can anyone confirm?
@auravulpes Wirewound would make sense in a context like that; it could also be a tempco but I don't see why that would be specified for a resistor in a cheap power supply unless there's some sort of current sensing going on using that resistor (but if you're doing current sensing to the point where you need a specified tempco, you need to also be able to measure the temperature and i don't see any sort of temperature measurement happening here)
@auravulpes It could be, but why would you use more expensive resistors when cheaper ones are also available?
That positioning suggests it's part of a capacitive dropper, incidentally.
@Felthry Like I said, you never really know with cheap electronics. That said, you're probably right about it not being one.
Also, it's not a capacitive dropper. It's using a transformer to step down the voltage
@emptyfortress No, the second gold band is definitely tolerance.
@Felthry No, there's not temperature measuring circuitry there. It's literally just sitting between one of the mains inputs and the bridge rectifier. The only reason I can think of that it'd specified the tempco is because it just happened to be the resistors they had lying around (which, in a cheap power supply, I suppose you'd never know)