looking up what exactly the gauge boson of the voltage gauge is and, uh, thanks duckduckgo, that's a useful suggestion
took a bit to find because we don't know the proper terminology but it seems like it's the photon, like we'd thought.
@Felthry Yuh, photons are the gauge bosons for the EM interaction/field. :3
@kellerfuchs I thought that was the case but I wasn't certain whether the B boson came into it anywhere and wanted to be sure before putting the information into our master's thesis!
@Felthry Ooooh, fancies; what's the thesis about? :3
Regarding the B boson, IIRC there's something about it and W3 being precursors to the photon (and Z?), prior to spontaneous symetry breaking.
It all goes very much over my head though :3
@kellerfuchs Right, the B, W, and Z bosons are the gauge bosons of the electroweak interaction, but the B and W bosons mix to produce the photon and the W⁺ and W⁻ bosons as we understand it
the thesis is about something entirely unrelated to this, but the concept of voltage being a gauge quantity comes up and I thought it might be relevant to mention. It probably won't be in the final product
@kellerfuchs so the electroweak gauge bosons are the B⁰, W⁺, W⁰, and W⁻, and the two neutral members mix to produce the Z⁰ and γ
@kellerfuchs Quantum physics is Fun™.
@Felthry Yuh.
And I still would like to know what's your thesis about (if you feel like sharing), even if it's unrelated :3
@kellerfuchs Modelling common-mode voltage, specifically including nonideal components, and how to mitigate EMI at specific harmonics.
@Felthry There are some words I know there :O
*is big dumm kitty.*
What's common-mode voltage?
@kellerfuchs the common and differential modes are two orthogonal components of the voltage in a circuit; basically, if you have the measured voltages on two lines of V₁ and V₂, you can define Vdm as V₁-V₂ and Vcm as (V₁+V₂)/2. Differential mode quantities are almost always the only ones of interest, but CM quantities also contribute to noise and EMI.
@kellerfuchs oh, no, I had it wrong, the W⁰ and B⁰ bosons mix to form the Z⁰ and photon. I _thought_ that getting three out of two seemed wrong