Fun with C
Much as I enjoy C, there are times I'm reminded of delightful traps.
Say you've got this code:
uint16_t a,b;
uint32_t result;
result = a * b;
No problem, right? No warnings, nothing.
Not quite. =:)
It's that arithmetic operator. If it sees any args less than the bit width of int, they get automatically promoted to ints - not unsigned ints, just plain signed ints. So, you wind up with a warning that conversion to uint32_t from int may change the sign of the result.
What you want to do in that case is preempt the compiler by typecasting both a and b to uint32_t; being (assuming an int width of 32 bits!) 32 bits, same as int, those signed promotions don't take place,
Fun. ^_^
re: Fun with C
@porsupah Warning: Implicit conversion of unsigned ints may result in your probe crashing into mars.
